No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! Let's say, x be the number which when divided by 6,9,15,18 leaves remainder 0. This implies (x+4) must leave remainder 4 when divided by the above numbers.The least number to satisfy the above condition is the LCM of the above numbers which is 90. So, x=90. x+4=94 But 94 is not a multiple of 7. With the help of hit and trial method,we can get x=180,x+4=184 but not a multiple of 7. x=270,x+4=274 but not a multiple of 7. x=360,x+4=364. 364 leaves remainder 4 when divided by 6,9,15 and 18.And is also a multiple of 7. Hence,364 is the least number satisfying all the conditions. |
What is the least multiple of 7 which leaves a remainder of 4 when divided by 6 9 15 and 18?
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