What mass of potassium nitrate would be needed to make a saturated solution in 10 g of water at 313 K ● 3.2 g ● 6.2 g ● 62 g ● 32 g?

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Text Solution

Solution : (i) Potassium nitrate is least soluble in water at 293 K. (ii) Potassium nitrate shows maximum change in its solubility which is 30 g (62-32) per 100 g of water. (iii) From the available information, 55 g of ammonium chloride solution upon cooling from 333 K to 293 K separates salt = (55 - 37) = 18 g. (iv) From the available information, it is clear that the solubility of salt in water increases with the rise in temperature At 293 K, in a saturated solution, 100 g of water has sodium chloride = 36 g 10 g of water has sodium chloride = 3.6 g

Hey!

The solution is as follows :

Solubility of potassium nitrate at 313K = 62/100 100 g of water contains potassium nitrate = 62 g 50 g of water contains potassium nitrate = 62/100 X 50 = 31g

Thus, 31 g potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 g of water at 313 K.

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