Text Solution
Solution : 11 L`->`4I,4S,2P,1M <br> `=> .^8C_4*(7!)/(4!*2!)` <br> `= .^8C_4 *(7 xx 6!)/(4!*2!)` <br> `= .^8C_4 .^6C_4 xx 7` <br> option 4 is correct