Write any two equations of the line which passes through the point 1 2

The taxi fare in a city is as follows: For the first kilometre, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.

Total distance covered = x kmTotal fare = Rs yFare for the first kilometre = Rs 8Subsequent distance = (x – 1) kmFare for the subsequent distance = Rs 5(x – 1)According to the question,y = 8 + 5 (x – 1)⇒ y = 8 + 5x – 5⇒ y = 5x + 3

Table of solutions

We plot the points (0, 3) and (1, 8) on the graph paper and join the same by a ruler to get the line which is the graph of the equation y = 5x + 3.

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Write the equation of the line which passes through $(1, –2)$ and is perpendicular to the line with equation $5y – x = 1$.

I know that I need to put the equation into slope-intercept form but what is the step that I take after this.

$$y = \frac 1 5 x + \frac 1 5$$

I read something about the negative reciprocal but that isn't working for me.

Also, here are the possible answers:

a. $5x + y = 3$ ANSWER