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The frequency difference is just the Larmor frequency x the chemical shift = 64 MHz x 1 ppm = (64 x 106 Hz) x (1.0 x 10−6) = 64 Hz. Link to Q&A discussion Field strength is doubled, so Larmor frequency is doubled, and frequency difference due to chemical shift is also doubled. The correct answer is therefore c). Link to Q&A discussion All statements are true except d). At equilibrium, M is stationary and aligned with the external magnetic field. Application of an RF-pulse is required to tip M out of alignment with B0 at which time it will begin to precess. Link to Q&A discussion In the absence of a strong external magnetic field, individual proton spins are randomly oriented in space and their vector sum is essentially zero in all directions. In reality, however, some small external magnetic field is always present, if only from the earth itself. Thus M is only effectively (but never completely zero) in all directions. Link to Q&A discussion Answer d) is correct because the spins have random transverse components of angular momentum. An RF-pulse or energy input near the Larmor frequency will be necessary to generate some phase coherence and transverse components. Link to Q&A discussion The initial growth of longitudinal magnetization (Mz) is a simple exponential with time constant T1. Link to Q&A discussion Only d) is false. Even though the individual spins comprising M are always precessing, M itself does not precess unless tipped out of alignment with B0 allowing it to develop nonzero transverse components. Once M is completely inverted 180° with respect to B0, it no longer has transverse components and is no longer precessing. If left alone after such an inversion, M will simply regrow along the z-axis to return to its initial orientation and magnitude aligned with B0. Link to Q&A discussion All statements are true except d). Nuclear precession is experienced by all non-zero spin particles when placed in an external magnetic field and requires no input of energy. NMR is a special condition of a spin system requiring the absorption and release of energy over a narrow range of frequencies. Link to Q&A discussion Back to top of page
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