What mass of sodium chloride would be needed to make a saturated solution in 10 g of water at 293K

Last updated at July 26, 2021 by

Answer

Here,

Solute is sodium chloride
Solvent is water .

Now,

Mass of solute = Mass of sodium chloride = 36g

Mass of solvent = Mass of water = 100g

Mass of solution = Mass of solute + Mass of solvent

= 36g + 100g

= 136g

Concentration of solution = (Mass of solute (g)/Mass of solution(g)) × 100%

= (36/136) × 100%

= 9 × 100/34 %

= 26.47 %

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Text Solution

Solution : At `30^@ C`, 36 g of sodium chloride is dissolved in 100 g of water. `therefore `Mass of sodium chloride that would be need for 100 g of water = 36 g `therefore ` Mass of sodium chloride dissolved in 50 g of 100 g of water `=( 36 xx 50 )/( 100 )= 18 g `

Text Solution

Solution : (a) Mass of potassium chloride in 100 g of water in saturated solution = 46 g Mass of potassium chloride in 50 g of water in saturated solution = `((46 g))/((100 g)) xx (50g) = 23 g` (b) When the solution is cooled, the solubility of salt in water will decrease. This means that upon cooling, it will start separating from the solution in crystalline form.

Text Solution

Solution : Mass of solute (sodium chloride)=36 g(Given) Mass of solvent (water)=100 g (Given) Then, mass of sodium = Mass of solute + Mass of solvent =(36+100 )g =136 g `=("Mass of Solute")/("Mass of Solvent")xx100%` `=(36)/(136)xx100%` =26.47%

Mass per cent is a way of expressing a concentration or describing the component in a particular mixture. The solution composition can be expressed in mass percentage that depicts the mass of solute present in a given mass of solution.

The quantity of solute is expressed in mass or by moles. For a solution, the mass per cent is described as the grams of solute per grams of solution, multiplied by 100 to get the percentage.

Concentration

Mass of sodium chloride (Solute) = 36gm Mass of water (solvent) = 100 gm

Mass of solution = 36+100

∴ Mass of solution = 136 gm

Concentration = (Mass of Solute / Mass of Solution) * 100

Concentration = (36/136) × 100

Concentration = 26.47%

Temperature

If temperature increases, solubility increases and if temperature decreases, solubility decreases.

It is possible to distinguish the particles of solute from those of solvent in a suspension, since particle size is bigger in suspensions, hence it is easier to distinguish the particles of solute.

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