On factorising 1600 into prime factors, we get: \[1600 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5\] On grouping the factors in triples of equal factors, we get: \[1600 = \left\{ 2 \times 2 \times 2 \right\} \times \left\{ 2 \times 2 \times 2 \right\} \times 5 \times 5\] It is evident that the prime factors of 1600 cannot be grouped into triples of equal factors such that no factor is left over. Therefore, 1600 is a not perfect cube. However, if the number is divided by (\[5 \times 5 = 25\]), the factors can be grouped into triples of equal factors such that no factor is left over. Thus, 1600 should be divided by 25 to make it a perfect cube. Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now |