What is the probability that the sum of the two numbers appearing on the top of the dice is 8

The number of possible outcomes =`6xx6=36` 

The outcomes favourble to the event the sum of the two number is 8=E={(2,6),(3,5),(4,4),(5,3),(6,2)}` 

The number of outcomes favourable to E= n(E) = 5 

Hence, `p(E)=(n(E))/(n(S))=5/36` 


Page 2

Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is: 

13 

The number of possible outcomes =`6xx6=36` 

There is no outcome favourable to the event E= `"the sum of two number is 13". ` 

n(E)=0 

Hence, `p(E)=(n(E))/(n(s))=0/36`

Concept: Type of Event - Complementry

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Page 3

Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is: 

less than or equal to 12

The number of possible outcomes = `6xx6=36` 

All the outcomes are favourable to the event E=`"sum of two number"<=12:` 

Hence, `p(E)=(n(E))/(n(S))=36/36=1`

Concept: Type of Event - Complementry

  Is there an error in this question or solution?