The number of possible outcomes =`6xx6=36` The outcomes favourble to the event the sum of the two number is 8=E={(2,6),(3,5),(4,4),(5,3),(6,2)}` The number of outcomes favourable to E= n(E) = 5 Hence, `p(E)=(n(E))/(n(S))=5/36` Page 2Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is: 13 The number of possible outcomes =`6xx6=36` There is no outcome favourable to the event E= `"the sum of two number is 13". ` n(E)=0 Hence, `p(E)=(n(E))/(n(s))=0/36` Concept: Type of Event - Complementry Is there an error in this question or solution? Page 3Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is: less than or equal to 12 The number of possible outcomes = `6xx6=36` All the outcomes are favourable to the event E=`"sum of two number"<=12:` Hence, `p(E)=(n(E))/(n(S))=36/36=1` Concept: Type of Event - Complementry Is there an error in this question or solution? |