CBSE 8 - Maths Asked by privacy | 12 Aug, 2021, 08:36: PM Find the length of each side of a rhombus whose diagonals are 24cm and 10cm long. Let ABCD be the rhombus with diagonals (AC = 24 cm and BD = 10 cm) meeting at O.We know that the diagonals of a rhombus bisect each other at angles. Applying Pythagoras theorem in right-angled AOB, we get: `AB^2=AO^2+BO^2=12^2+5^2` `AB^2=144+25=169` `AB=sqrt169=13 cm` Hence, the length of each side of the rhombus is 13 cm. Concept: Basic Proportionality Theorem (Thales Theorem) Is there an error in this question or solution? |