What is the equation of the line that passes through the point (1,1)(1,1) and has a slope of -5

B = y - mx

(-5,5) --> x=-5 and y = 5 with slope m=-1

SO then B = 5 - (-1)(-5)

= 5 - 5

= 0

y = mx +b = (-1)x + 0 = -x

Final equation is y = -x

Hi Dylan, You can use graphing to solve this problem by drawing the line on a coordinate plane. Begin by plotting the point (-5, 5) and count the slope of -1 (count one unit down, and one to the right) then plot your second point here. Draw your line to reveal your y-intercept then use the slope-intercept form y=mx+b to write your equation.

Equation is y= - x

The y-intercept is at (0,0) ... m (slope) = -1, b (y-intercept) = 0