What is the area of minor segment of a circle of radius 14 cm when its central angle is 60 also what is the area of corresponding major segment?

Find the area of the minor segment of a circle of radius 14 cm, when its central angle is 60˚. Also find the area of the corresponding major segment.[use π=22/7]

Radius of the circle = 14 cmCentral Angle, 𝜽 = 60°,

Area of the minor segment

`=theta/360^@xxpir^2-1/2r^2sintheta`

`=60^@/360^@xxpixx14^2-1/2xx14^2xxsin60^@`

`=1/6xx22/7xx14xx14-1/2xx14xx14xxsqrt3/2`

`=(22xx14)/3-49sqrt3`

`=(22xx14)/3-(147sqrt3)/3`

`=(308-147sqrt3)/3 cm^2`

Area of the minor segment= `(308-147sqrt3)/3 cm^2`

Concept: Areas of Sector and Segment of a Circle

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In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC, ∠ DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region.    Take π= 227                  

  Area of a trapezium = 24.5 cm212 AD + BC X AB = 24.5 Cm212 10+4 X AB = 24.5AB = 3.5 cm     r= 3.5 cmAreao of quadrant = 14x π r2                                = 0.25 x  227 x 3.5 x 3.5                                      = 9.625 cm2 The area of shaded region = 24. 5 - 9.625                                          = 14.875 cm2       

Find the area of the minor segment of a circle of radius 14 cm, when its central angle is 60∘. Also find the area of the corresponding major segment. [Use .π=22/7]

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