A and B can do a piece of work in = 40 daysB and C can do a piece of work in = 30 daysC and A can do a piece of work in = 24 days (A+B)’s 1-day work =`1/40` (B+C)’s 1-day work =`1/30` (C+A)’s 1-day work =`1/24` (i) [(A+B)+(B+C)+(C+A)]’s 1 day work = `1/4+1/30+1/24` `=(3+4+5)/120` `=12/120=1/10` i.e. (A+B+B+C+C+A)'s 1-day work =`1/10` i.e. 2 (A+B+C)'s 1-day work =`1/10` ∴ (A+B+C)'s 1-day work =`1/10xx1/2` `=1/20` ∴ (A+B+C) can do the work in = 20 days (ii) A's 1-day work =`1/20-1/30` `=(3-2)/60=1/60` ∴ A can do the work in 60 days B's 1-day work =`1/20-1/24` `=(6-5)/120=1/120` ∴ B can do the work in 120 days now, C's 1-day work =`1/20-1/40` `=(2-1)/40=1/40` C can do the work in 40 days Hence A can do the work in = 60 days B can do the work in = 120 days C can do the work in = 40 days
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Answer:
Every task necessitates a specific amount of time and a specific workforce, or the number of individuals who will complete the task. Work is usually categorised as a "1" unit. This time and and work concept is a follow-up to direct and inverse proportion. The given details are, A and B can do a piece of work in = 18 days Work done by A and B in 1 day = 1/18 B and C can do a piece of work in = 24 days Work done by B and C in 1 day = 1/24 A and C can do a piece of work in = 36 days Work done by A and C in 1 day = 1/36 By adding A, B and C we get, 2(A+B+C) one day work = 1/18 + 1/24 + 1/36 = (4+3+2)/72 (by taking LCM for 18, 24 and 36 which is 72) = 9/72 = 1/8 A+B+C one day work = 1/(8×2) = 1/16 ∴ A, B and C together can finish the work in = 1/(1/16) = 16days.
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