Bagaimana Anda mencetak karakter berurutan dengan python?

Kode sumber

# creating the aay a = [18, 18, 18, 6, 3, 4, 9, 9, 9] l = len(a) for i in range(l - 2): if a[i] == a[i + 1] and a[i + 1] == a[i + 2]: print(a[i])

Keluaran

18 9 _Untuk mendownload file mentah Klik Disini

Ketika diperlukan untuk menemukan string karakter berurutan yang berjarak sama, pemahaman daftar, operator 'semua' dan metode 'ord' digunakan

Contoh

Di bawah ini adalah demonstrasi yang sama

my_list = ["abc", "egfg", "mpsv", "abed", 'xzbd', 'agms'] print("The list is :") print(my_list) my_result = [sub for sub in my_list if all(ord(sub[index + 1]) - ord(sub[index]) == ord(sub[1]) - ord(sub[0]) for index in range(0, len(sub) - 1))] print("The resultant list is :") print(my_result)

Keluaran

The list is : ['abc', 'egfg', 'mpsv', 'abed', 'xzbd', 'agms'] The resultant list is : ['abc', 'mpsv', 'agms']

Penjelasan

• Daftar nilai string ditentukan dan ditampilkan di konsol

• Pemahaman daftar digunakan untuk beralih melalui daftar

• Operator 'semua' bersama dengan metode 'ord' digunakan untuk memeriksa apakah perbedaan antara indeks berikutnya dan indeks saat ini setara dengan indeks pertama dan indeks nol

  Seseorang di komentar khawatir Anda menginginkan jumlah total angka jadi "11100111" -> {"1":6, "0":2}. Dalam hal ini Anda ingin menggunakan a

  from collections import Counter s = "11100111" result = Counter(s) # {"1":6, "0":2} _

  Metode Anda

  Seperti yang telah ditunjukkan banyak orang, metode Anda gagal karena Anda mengulang [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 1 tetapi menangani [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 2. Hal ini menyebabkan kesalahan off-by-one ketika [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 3 menunjuk pada indeks terakhir [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 4, jadi [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 5 memunculkan [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 6. Salah satu cara untuk memperbaikinya adalah dengan mengulangi [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 7, tetapi lebih pythonic untuk menghasilkan sesuatu untuk diulang

  Untuk string yang tidak terlalu besar, [("1": 3), ("0", 3), ("2", 3), ("3", 2), ("4", 2), ("5", 5)] 8 bukan masalah kinerja, jadi Anda bisa melakukannya

  counts = [] count = 1 for a, b in zip(s, s[1:]): if a==b: count += 1 else: counts.append((a, count)) count = 1

  Satu-satunya masalah adalah Anda harus membuat huruf khusus pada karakter terakhir jika itu unik. Itu bisa diperbaiki dengan

  import itertools counts = [] count = 1 for a, b in itertools.zip_longest(s, s[1:], fillvalue=None): if a==b: count += 1 else: counts.append((a, count)) count = 1

  Jika Anda memiliki string yang sangat besar dan tidak tahan untuk menyimpan dua di antaranya dalam memori sekaligus, Anda dapat menggunakan

  Idenya adalah untuk melintasi string dari kiri ke kanan. Untuk setiap karakter yang dilintasi, cetak dalam satu baris jika berturut-turut dengan yang sebelumnya, jika tidak, cetak karakter baris baru.  

  Penerapan

  C++

  
  

  
  
  

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  ________137# creating the aay a = [18, 18, 18, 6, 3, 4, 9, 9, 9] l = len(a) for i in range(l - 2): if a[i] == a[i + 1] and a[i + 1] == a[i + 2]: print(a[i])_137_______8

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  Kompleksitas Waktu. Pada)
  Ruang Bantu. O(1)

  Artikel ini disumbangkan oleh Rakesh Kumar. Jika Anda menyukai GeeksforGeeks dan ingin berkontribusi, Anda juga dapat menulis artikel menggunakan tulis. geeksforgeeks. org atau kirimkan artikel Anda ke review-team@geeksforgeeks. org. Lihat artikel Anda muncul di halaman utama GeeksforGeeks dan bantu Geeks lainnya.  

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