At what depth from the earths surface the acceleration due to gravity g will be half the value of g at the surface take radius of earth 6400 km?

Text Solution

Solution : If the acceleration due to gravity on the earth.s surface is g, then at a depth h below the earth.s surface, <br> `g^.=g(1-h/R)=g-(gh)/R` <br> `therefore` Decrease in value ,`g-g^.=(gh)/R` <br> As per the question , <br> `(gh)/R=0.01g` <br> or, `h=0.01xxR=0.01xx6400 =64 km`.

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